How to exclude child_of from wp_list_pages?

You can use the Exclude Pages plugin to exclude the individual child pages via a checkbox in the edit page screen.

This still doesn’t do exactly what you need but it’s a good plugin for page by page control of what appears in menus.

Thanks Stevie!
That’s nice but I need to setup this in order the editors of the website don’t have to worry about this exclude pages in the future. I need a definite solution… any ideas?

The template tag, wp_list_pages(), has an exclude_tree argument you might consider.

thank you Michael!
yess i saw that… but i need to exclude only the child (and new child will be created by the editors) not the parent, how to do it?

<?php
$child_ids = $wpdb->get_col("SELECT ID FROM $wpdb->posts WHERE $wpdb->posts.post_parent = 134  AND $wpdb->posts.post_type = 'page' AND $wpdb->posts.post_status = 'publish' ORDER BY $wpdb->posts.ID ASC");
$exclude = implode($child_ids,', ');
wp_list_pages('exclude=' . $exclude . '&title_li=<h2>' . __('Pages') . '</h2>');
?>

Could you just exclude it from the list_pages command and add it to the end seperately, or does it have to appear in order?

<ul>
wp_list_pages ('sort_column=menu_order&title_li=&echo=0&depth=3&exclude=134');
wp_list_pages ('sort_column=menu_order&title_li=&echo=0&depth=1&include=134');
</ul>

Not sure if that is what you need.

MichaelH,

I have the following:

global $wpdb;

$child_ids = $wpdb->get_col("SELECT ID FROM $wpdb->posts WHERE $wpdb->posts.post_parent = 18  AND $wpdb->posts.post_type = 'page' AND $wpdb->posts.post_status = 'publish' ORDER BY $wpdb->posts.ID ASC");

$exclude = implode($child_ids,', ');

wp_list_pages('exclude=' . $exclude . '&sort_column=menu_order&title_li=');

And as a result I get the expected list of links, followed by an unexpected list of the excluded pages. What am I doing wrong?

Thx in advance!