Using variable passed in URL

  • Resolved circleatseven

    (@circleatseven)


    13 years, 6 months ago

    I’m able to pass a variable in a url like so:
    https://mysite.com/?searchterm=544

    .. and I am able to GET the variable and display it in a php echo like so (this is placed before the loop):

    <?php $searchterm = $_GET["searchterm"]; ?>
Search term: <?php echo $searchterm; ?>

    BUT if I insert the echo in the query_post like so:

    <?php query_posts('p=<?php echo $searchterm; ?>');
	if ( have_posts() ) : while ( have_posts() ) : the_post();
?>

    … it doesn’t seem to work correctly, but if I manually enter 544 in place of the echo it works as expected.

    Any ideas!? Thanks

Viewing 3 replies - 1 through 3 (of 3 total)

  • If you’re trying to implement a custom term to search on, I would take a look at the Custom Queries Codex page. You’ll need to define your custom terms, possibly add some rewrite rules depending on whether or not you use permalinks.

    Thread Starter circleatseven

    (@circleatseven)

    Thanks, but that’s not really what I’m trying to do. I should’ve used a different variable name instead of “$searchterm”… sorry if that made it confusing.

    All I really need to do is simply insert that variable from the url (‘544’) into the query_post so I can display a specific post (id of ‘544’) in a page… it would look like this:

    <?php query_posts('p=544');
	if ( have_posts() ) : while ( have_posts() ) : the_post();
?>

    thanks again

    Thread Starter circleatseven

    (@circleatseven)

    Figured it out – just changed the single quotations to double and it worked…

    Changed:

    <?php query_posts( 'p=<?php echo $searchterm; ?>' );
	if ( have_posts() ) : while ( have_posts() ) : the_post();
?>

    To:

    <?php query_posts( "p=<?php echo $searchterm; ?>" );
	if ( have_posts() ) : while ( have_posts() ) : the_post();
?>

    Ugh.

Viewing 3 replies - 1 through 3 (of 3 total)
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