Conditions for exit page popup

  • Resolved mac512k

    (@mac512k)


    2 years, 9 months ago

    I’m trying to create a condition so that if a viewer lands on a page of the website – once they leave that page to another page on the website a pop up will open after a few seconds so …

    user lands on {landing page} > user visits another page on same website > pop up triggers because they left the {landing page}.

    You only see the pop up because the user was on a specific page and left that page.

Viewing 2 replies - 1 through 2 (of 2 total)
  • Plugin Support Nebu John – WPMU DEV Support

    (@wpmudevsupport14)

    Hi @mac512k,

    Trust you are doing good, and thank you for reaching out to us.

    You can configure the visibility rule based on the source of the arrival. Suppose the Source of Arrival in visibility rules are configured as ‘An Internal page’. In that case, the pop-up will be visible when the page is navigated from the arrival page to another.

    Please find more details in our documentation here: https://wpmudev.com/docs/wpmu-dev-plugins/hustle/#visibility-modules

    Please feel free to contact us if you need further assistance.

    Kind Regards,
    Nebu John

    Plugin Support Nithin – WPMU DEV Support

    (@wpmudevsupport11)

    Hi @mac512k,

    Since we haven’t heard from you for a while. I’ll mark this thread as resolved for now. Please feel free to re-open the thread if you need further assistance.

    Best Regards
    Nithin

Viewing 2 replies - 1 through 2 (of 2 total)
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