If Page 1 then show DIV – how?

<?php if( !is_paged() ) { ?>
<div> what ever </div>
</php } ?>

meaning: if it is not paged, then show the div

https://www.w3schools.com/php/php_if_else.asp

https://php.net/manual/en/language.operators.logical.php

https://codex.www.ads-software.com/Function_Reference/is_paged

when I type that, it shows this error:

Parse error: syntax error, unexpected $end in …/wordpress/wp-content/themes/mousejunkies/home.php on line 36

line 36 is the last line of code

Here is what I have as my code for home.php:


<?php get_header(); ?>

<div id="wrap">
<div id="content">

<?php if( !is_paged() ) { ?>
<div class="page" id="homeTop">
HERE IS THE DIV
</div>
</php } ?>

<?php if (have_posts()) : ?>

<?php while (have_posts()) : the_post(); ?>

<div class="post">
<h1 class="postTitle">"><?php the_title(); ?></h1>
<small class="postMeta">On <?php the_time('F jS, Y'); ?> in <?php the_category(', '); ?></small>
<p class="postExcerpt"><?php the_excerpt(); ?></p>
<p class="postMore">">Continue Reading</p>
</div> <!-- END POST -->

<?php endwhile; ?>

<?php wp_pagenavi(); ?>

<?php else : ?>
<h1>Nothing Found</h1>
<p>Sorry, but what you are looking for has not been found, try searching for it.</p>
<?php endif; ?>

</div> <!-- END CONTENT -->

<?php get_sidebar(); ?>

<?php get_footer(); ?>

my typo; needs to be a proper php tag in the last line :-(:

corrected:

<?php if( !is_paged() ) { ?>
<div> what ever </div>
<?php } ?>

Awesome, thank you so much!