one checkbox always ticked

Hi @vjdoon,

I hope you are keeping well today.

An out-of-the-box solution is not available for this, however, I have asked our code experts to check if a workaround could be suggested. We’ll inform you here if a workaround could be suggested.

Kind Regards,
Nebu John

Hello @vjdoon,

Please try adding the following PHP snippet.

Save it as a PHP file, and upload it to /wp-content/mu-plugins/ directory, to make it run as a must use plugin:

<?php
add_action( 'wp_footer', 'wpmudev_keep_checkbox_disabled', 9999 );
function wpmudev_keep_checkbox_disabled() {
    global $post;
    if ( is_a( $post, 'WP_Post' ) && ! has_shortcode( $post->post_content, 'forminator_form' ) ) {
        return;
    }
	?>
	<script type="text/javascript">
	jQuery( document ).ready( function($){
		setTimeout(function() {
			$('.forminator-custom-form').trigger('after.load.forminator');
		},100);

		$(document).on('after.load.forminator', function(event, form_id) {
            if ( event.target.id == 'forminator-module-6' ) { // Please change the form ID.
                $('#checkbox-1 input:checked').attr('disabled', 'disabled');
            }
        });
    });
    </script>
    <?php
}

Replace 6 with your form ID on this line:

if ( event.target.id == 'forminator-module-6' ) { // Please change the form ID.

and checkbox-1 with your checkbox field name in this part:

$('#checkbox-1 input:checked').attr('disabled', 'disabled');

Let us know if you have any questions!
Best Regards,
Dmytro

Hi,
Thanks for the code snippet, I tried it on this link https://mytestsite.in/rscdemo/temp/ but it is not working. ( In this form, my requirement is that “General Entry” option of Entry type always remains checked and the user should not be able to uncheck it

Hi @vjdoon,

I hope you are doing well today!

Please share an export of the form with us, so that we can check further.

You can find more info on how to export the form here : https://wpmudev.com/docs/wpmu-dev-plugins/forminator/#import-export

After exporting, please share the code using a services such as https://pastebin.com or https://justpaste.it/ which is free to use.

Please always make sure to use such service to share the code and don’t post the code here directly as it will most likely be unusable.

Kind regards,
Zafer

Hi,

please find the exported form on this link https://jpst.it/3whm5

Hi again @vjdoon,

We have tested the code snippet after importing your form and it was working well. Your form ID seems to be 658, so the code should look like this.

<?php
add_action( 'wp_footer', 'wpmudev_keep_checkbox_disabled', 9999 );
function wpmudev_keep_checkbox_disabled() {
    global $post;
    if ( is_a( $post, 'WP_Post' ) && ! has_shortcode( $post->post_content, 'forminator_form' ) ) {
        return;
    }
	?>
	<script type="text/javascript">
	jQuery( document ).ready( function($){
		setTimeout(function() {
			$('.forminator-custom-form').trigger('after.load.forminator');
		},100);

		$(document).on('after.load.forminator', function(event, form_id) {
            if ( event.target.id == 'forminator-module-658' ) { // Please change the form ID.
                $('#checkbox-1 input:checked').attr('disabled', 'disabled');
            }
        });
    });
    </script>
    <?php
}

You can find more information below on how to use mu-plugins.
https://wpmudev.com/docs/using-wordpress/installing-wordpress-plugins/#installing-mu-plugins
and
https://www.ads-software.com/support/article/must-use-plugins/

Kind regards,
Zafer

The code is working as intended,but upon submitting the form without checking any other box it gives an error “Error: Your form is not valid, please fix the errors!”

Hi again @vjdoon,

We are checking the issue with our SLS (Second Line Support) team and will inform you accordingly.

Thanks for the patience while we are looking into this.

Kind regards,
Zafer

Hi again @vjdoon,

Please replace the following line in code

$('#checkbox-1 input:checked').attr('disabled', 'disabled');

with this and try again

$('#checkbox-1 input:checked').on('click', function(){
$(this).prop("checked", true);
});

Kind regards,
Zafer

works perfectly! thanks