PHP date

  • Im not sure if this is the place to ask this , but here goes.

    Im trying to create a php code that echo′s a text if date exceeds today
    else echo something else…

    Is this correct ? :

    <?php
$t = date("");

if ($t > "today") {
    echo "It has started";
} else {
    echo "It has not started";
}
?>
Viewing 1 replies (of 1 total)
  • Geoffrey Shilling

    (@geoffreyshilling)

    Volunteer Moderator

    How about:

    <?php
$t = date("");

if ($t > date("Y/m/d")) {
    echo "It has started";
} else {
    echo "It has not started";
}
?>

    There are quite a few formats you can use for the date

    <?php
// Assuming today is March 10th, 2001, 5:16:18 pm, and that we are in the
// Mountain Standard Time (MST) Time Zone

$today = date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today = date("m.d.y");                         // 03.10.01
$today = date("j, n, Y");                       // 10, 3, 2001
$today = date("Ymd");                           // 20010310
$today = date('h-i-s, j-m-y, it is w Day');     // 05-16-18, 10-03-01, 1631 1618 6 Satpm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.');   // it is the 10th day.
$today = date("D M j G:i:s T Y");               // Sat Mar 10 17:16:18 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:18 m is month
$today = date("H:i:s");                         // 17:16:18
$today = date("Y-m-d H:i:s");                   // 2001-03-10 17:16:18 (the MySQL DATETIME format)
?>

    More on the date function: https://php.net/manual/en/function.date.php

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