Returns "Array"

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  • If your template is using “get_sub_field(‘some_label_for_link_content’)”, the value for this is an array. To get the link, you can output like so:

    <?php
$link_array = get_sub_field('fieldname_for_your_link_content');
echo array_values($link_array)[0]; // URL
?>

    sorry, i am a nub.

    I have the same Error… where do i have to put the php code provided?

    thx

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